如图3(a),若假想刀尖P沿工件轮廓AB移动(即P1P2与AB重合),并按AB尺寸编程,则必然产生ABCD的残留误差。为此,应如图3(b)所示,使圆头刀的切削点移至AB,并沿AB移动,从而避免了残留误差。但这时假想刀尖的轨迹为P3P4,它与轮廓AB在X向相差⊿X,Z向相差⊿Z。设刀具半径为r,不难求得:
⊿X=r[2/(1 + ctg eq \o(\s\do-8(θ),\s\do 0(—),\s\do 8(2)))] ⊿Z=r(1 - tg eq \o(\s\do-8(θ),\s\do 0(—),\s\do 8(2)))
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